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Рассчитайте мольные и массовые доли элементов, входящих в состав красного железняка Fe2O3, сернистого газа SO2, известняка CaCO3.
Ответ: |
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Дано: | Решение |
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`"1) "Fe_2O_3` `"2) "SO_2` `"3) "CaCO_3` |
1) `ω(Fe) = (100*n(Fe)*M(Fe))/(M(Fe_2O_3)) = (100*2*56)/160 = 70%` `χ(Fe) = (100*n(Fe))/(n(Fe) + n(O)) = (100*2)/(2 + 3) = 40%` `ω(O) = (100*n(O)*M(O))/(M(Fe_2O_3)) = (100*3*16)/160 = 30%` `χ(O) = (100*n(O))/(n(Fe) + n(O)) = (100*3)/(2 + 3) = 60%` 2) `ω(S) = (100*n(S)*M(S))/(M(SO_2)) = (100*1*32)/64 = 50%` `χ(S) = (100*n(S))/(n(S) + n(O)) = (100*1)/(1 + 2) = 33.3%` `ω(O) = (100*n(O)*M(O))/(M(SO_2)) = (100*2*16)/64 = 50%` `χ(O) = (100*n(O))/(n(S) + n(O)) = (100*2)/(1 + 2) = 66.7%` 3) `ω(Ca) = (100*n(Ca)*M(Ca))/(M(CaCO_3)) = (100*1*40)/100 = 40%` `χ(Ca) = (100*n(Ca))/(n(Ca) + n(C) + n(O)) = (100*1)/(1 + 1 + 3) = 20%` `ω(C) = (100*n(C)*M(C))/(M(CaCO_3)) = (100*1*12)/100 = 12%` `χ(C) = (100*n(C))/(n(Ca) + n(C) + n(O)) = (100*1)/(1 + 1 + 3) = 20%` `ω(O) = (100*n(O)*M(O))/(M(CaCO_3)) = (100*3*16)/100 = 48%` `χ(O) = (100*n(O))/(n(Ca) + n(C) + n(O)) = (100*3)/(1 + 1 + 3) = 60%` |
`ω("элементов") = ?` `χ("элементов") = ?` |