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Вычислите массовые доли элементов в следующих соединениях:
а) H3PO4; б) Na2SiO3; в) BaSO4; г) KClO3.
а)
Ответ: `ω(H) = 3.1%`, `ω(P) = 31.6%`, `ω(O) = 65.3%`. |
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| Дано: | Решение |
|---|---|
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`H_3PO_4` |
`ω(H) = (100*k*A_r(H))/(M_r(H_3PO_4)) = (100*3*1)/98 = 3.1%` `ω(P) = (100*k*A_r(P))/(M_r(H_3PO_4)) = (100*1*31)/98 = 31.6%` `ω(O) = (100*k*A_r(O))/(M_r(H_3PO_4)) = (100*4*16)/98 = 65.3%` |
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`ω(H) = ?` `ω(P) = ?` `ω(O) = ?` |
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б)
Ответ: `ω(Na) = 37.7%`, `ω(Si) = 23%`, `ω(O) = 39.3%`. |
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| Дано: | Решение |
|---|---|
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`Na_2SiO_3` |
`ω(Na) = (100*k*A_r(Na))/(M_r(Na_2SiO_3)) = (100*2*23)/122 = 37.7%` `ω(Si) = (100*k*A_r(Si))/(M_r(Na_2SiO_3)) = (100*1*28)/122 = 23%` `ω(O) = (100*k*A_r(O))/(M_r(Na_2SiO_3)) = (100*3*16)/122 = 39.3%` |
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`ω(Na) = ?` `ω(Si) = ?` `ω(O) = ?` |
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в)
Ответ: `ω(Ba) = 58.8%`, `ω(S) = 13.7%`, `ω(O) = 27.5%`. |
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| Дано: | Решение |
|---|---|
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`BaSO_4` |
`ω(Ba) = (100*k*A_r(Ba))/(M_r(BaSO_4)) = (100*1*137)/233 = 58.8%` `ω(S) = (100*k*A_r(S))/(M_r(BaSO_4)) = (100*1*32)/233 = 13.7%` `ω(O) = (100*k*A_r(O))/(M_r(BaSO_4)) = (100*4*16)/233 = 27.5%` |
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`ω(Ba) = ?` `ω(S) = ?` `ω(O) = ?` |
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г)
Ответ: `ω(K) = 31.8%`, `ω(Cl) = 29%`, `ω(O) = 39.2%`. |
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| Дано: | Решение |
|---|---|
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`KClO_3` |
`ω(K) = (100*k*A_r(K))/(M_r(KClO_3)) = (100*1*39)/122.5 = 31.8%` `ω(Cl) = (100*k*A_r(H))/(M_r(KClO_3)) = (100*1*35.5)/122.5 = 29%` `ω(O) = (100*k*A_r(O))/(M_r(KClO_3)) = (100*3*16)/122.5 = 39.2%` |
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`ω(K) = ?` `ω(Cl) = ?` `ω(O) = ?` |
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